0=-13x^2+104x

Solution for 0=-13x^2+104x equation:

0=-13x^2+104x

We move all terms to the left:

0-(-13x^2+104x)=0

We add all the numbers together, and all the variables

-(-13x^2+104x)=0

We get rid of parentheses

13x^2-104x=0

a = 13; b = -104; c = 0;
Δ = b2-4ac
Δ = -1042-4·13·0
Δ = 10816
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{10816}=104$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-104}{2*13}=\frac{0}{26}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+104}{2*13}=\frac{208}{26}
=8
$